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I'm running Python 3.6.3 and trying to just django_gulp 3.0.0.
$ python manage.py runserver
>>> Starting gulp
<class 'django.core.management.base.OutputWrapper'> <class 'django.core.management.base.OutputWrapper'>
Traceback (most recent call last):
File "/usr/local/Cellar/python3/3.6.3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/concurrent/futures/thread.py", line 56, in run
result = self.fn(*self.args, **self.kwargs)
File "/Users/rzg/Projects/2017/10/cocktails-ii/.direnv/python-3.6.3/lib/python3.6/site-packages/django_gulp/management/commands/runserver.py", line 112, in start_gulp
stderr=self.stderr)
File "/usr/local/Cellar/python3/3.6.3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 667, in __init__
errread, errwrite) = self._get_handles(stdin, stdout, stderr)
File "/usr/local/Cellar/python3/3.6.3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/subprocess.py", line 1184, in _get_handles
c2pwrite = stdout.fileno()
io.UnsupportedOperation: fileno
>>> Killing pid 36211
>>> Exiting
What seems to be happening is that start_gulp calls subprocess.Popen and passes self.stdout, which is an instance of django.core.management.base.OutputWrapper. This class in turn wraps a _io.TextIOWrapper, which does not necessarily have an associated file descriptor number.
The text was updated successfully, but these errors were encountered:
I'm running Python 3.6.3 and trying to just django_gulp 3.0.0.
What seems to be happening is that
start_gulp
callssubprocess.Popen
and passesself.stdout
, which is an instance ofdjango.core.management.base.OutputWrapper
. This class in turn wraps a_io.TextIOWrapper
, which does not necessarily have an associated file descriptor number.The text was updated successfully, but these errors were encountered: